(300-3x^2)/(2x-20)=0

Solution for (300-3x^2)/(2x-20)=0 equation:

(300-3x^2)/(2x-20)=0


Domain of the equation: (2x-20)!=0

We move all terms containing x to the left, all other terms to the right

2x!=20

x!=20/2

x!=10

x∈R


We multiply all the terms by the denominator


(300-3x^2)=0

We get rid of parentheses

-3x^2+300=0

a = -3; b = 0; c = +300;
Δ = b2-4ac
Δ = 02-4·(-3)·300
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-3}=\frac{-60}{-6}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-3}=\frac{60}{-6}
=-10
$